# Problem: Below is a representation of 50 atoms of a fictitious element called westmontium (Wt). The red spheres represent Wt-296, the blue spheres Wt-297, and the green spheres Wt-298. The mass of each Wt isotope is measured relative to C-12 and tabulated below. Use the mass of C-12 to convert each of the masses to amu and calculate the atomic mass of Wt.IsotopeMassWt-29624.6631 12 C)Wt-29724.7486 12 C)Wt-29824.8316 12 C)

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###### FREE Expert Solution

Mass Wt-296 = 24.6631 x 12 amu = 295.9572 amu

Mass Wt-297 = 24.7486 x 12 amu = 296.9832 amu

Mass Wt-298 = 24.8316 x 12 amu = 297.9792 amu ###### Problem Details

Below is a representation of 50 atoms of a fictitious element called westmontium (Wt). The red spheres represent Wt-296, the blue spheres Wt-297, and the green spheres Wt-298. The mass of each Wt isotope is measured relative to C-12 and tabulated below. Use the mass of C-12 to convert each of the masses to amu and calculate the atomic mass of Wt.

 Isotope Mass Wt-296 24.6631 12 C) Wt-297 24.7486 12 C) Wt-298 24.8316 12 C)