Problem: Boron has only two naturally occurring isotopes. The mass of boron-10 is 10.01294 amu and the mass of boron-11 is 11.00931 amu .Use the atomic mass of boron to calculate the relative abundance of boron-10.

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Atomic Mass=[mass×f.a.]isotope 1+[mass×f.a.]isotope 2


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Boron has only two naturally occurring isotopes. The mass of boron-10 is 10.01294 amu and the mass of boron-11 is 11.00931 amu .

Use the atomic mass of boron to calculate the relative abundance of boron-10.

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