Use the conversion factor 1 in = 2.54 cm to find the volume

$\mathrm{V}=\frac{4}{3}{\mathrm{\pi r}}^{3}\phantom{\rule{0ex}{0ex}}\mathrm{V}=\frac{4}{3}\left(3.14\right){\left(\left(0.935\mathrm{in}\right)\left(\frac{2.54\mathrm{cm}}{1\mathrm{in}}\right)\right)}^{3}\phantom{\rule{0ex}{0ex}}\mathrm{V}=56.08{\mathrm{cm}}^{3}$

A pure copper sphere has a radius 0.935 in .

How many copper atoms does it contain? [The volume of a sphere is (4/3)r^{3} and the density of copper is 8.96 g/cm^{3}.]

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