# Problem: Section 1.7 showed that in 1997 Los Angeles County air had carbon monoxide (CO) levels of 15.0 ppm. An average human inhales about 0.50 L of air per breath and takes about 20 breaths per minute.How many milligrams of carbon monoxide does the average person inhale in an 8 hour period for this level of carbon monoxide pollution? Assume that the carbon monoxide has a density of 1.2 g/L. (Hint: 15.0 ppm CO means 15.0 L per 106 air.)

###### FREE Expert Solution

The following steps have to be taken to determine the mass (in milligrams) of CO inhaled:

Step 1: Finding the Volume of air inhaled in 8 hours.

The Volume of CO inhaled per breath = 0.5 L

We can use the following conversion to find the volume of air inhaled in 8 h.

Recall that, 1 hour = 60 min The volume of air inhaled in 8 hours by an average human is 4800 L.

80% (180 ratings) ###### Problem Details

Section 1.7 showed that in 1997 Los Angeles County air had carbon monoxide (CO) levels of 15.0 ppm. An average human inhales about 0.50 L of air per breath and takes about 20 breaths per minute.

How many milligrams of carbon monoxide does the average person inhale in an 8 hour period for this level of carbon monoxide pollution? Assume that the carbon monoxide has a density of 1.2 g/L. (Hint: 15.0 ppm CO means 15.0 L per 106 air.)

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