We are asked to **calculate for the mass of ore required to make a lead (Pb) sphere with a 6.00 cm radius**.

To solve this problem, we shall follow these steps:

*Step 1*: Determine the volume of the sphere.

*Step 2*: Using density, determine the mass of the ore required to make the lead sphere.

**Step 1****: The equation for the ****volume of a sphere ****is given as:**

**$\overline{){\mathbf{V}}{\mathbf{o}}{\mathbf{l}}{\mathbf{u}}{\mathbf{m}}{{\mathbf{e}}}_{\mathbf{s}\mathbf{p}\mathbf{h}\mathbf{e}\mathbf{r}\mathbf{e}}{\mathbf{=}}\left(\frac{\mathbf{4}}{\mathbf{3}}\right)\left(\mathbf{\pi}\right){{\mathbf{r}}}^{{\mathbf{3}}}}$**

*Where **π **= 3.1416 (constant)*

Lead metal can be extracted from a mineral called galena, which contains 86.6% lead by mass. A particular ore contains 68.5% galena by mass.

If the lead can be extracted with 92.5% efficiency, what mass of ore is required to make a lead sphere with a 6.00 cm radius?

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Dimensional Analysis concept. You can view video lessons to learn Dimensional Analysis. Or if you need more Dimensional Analysis practice, you can also practice Dimensional Analysis practice problems.

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Based on our data, we think this problem is relevant for Professor Derakhshan's class at CSULB.