• Solutions 16
Sign up for free to keep watching this solution

Solution: How many millimoles of Ca(NO3)2 contain 4.78 × 1022 formula ...

Question

How many millimoles of Ca(NO3)2 contain 4.78 × 1022 formula units of Ca(NO3)2? The molar mass of Ca(NO3)2 is 164.10 g/mol.

A) 12.6 mmol Ca(NO3)2

B) 13.0 mmol Ca(NO3)2

C) 20.7 mmol Ca(NO3)2

D) 79.4 mmol Ca(NO3)2

E) 57.0 mmol Ca(NO3)2