H can't be the central atom: P is the central atom
Total number of valence electrons present:
Group Valence Electrons
P 5A 1 × 5 e– = 5 e–
H 1A 4 × 1 e– = 4 e–
From +1 charge: Subtract: 1 e–
Total: 8 valence e–
H forms only one bond
Draw a Lewis structure for
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Our tutors have indicated that to solve this problem you will need to apply the Lewis Dot Structure concept. You can view video lessons to learn Lewis Dot Structure. Or if you need more Lewis Dot Structure practice, you can also practice Lewis Dot Structure practice problems.
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Based on our data, we think this problem is relevant for Professor Schurmeier's class at UCSD.
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Our data indicates that this problem or a close variation was asked in Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition. You can also practice Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition practice problems.