Problem: Some species consisting of just two oxygen atoms are the oxygen molecule, O 2; the peroxide ion, O22−; the superoxide ion, O 2−; and the dioxygenyl ion, O 2+. Draw an MO diagram for each, rank the species in order of increasing bond length, and find the number of unpaired electrons in each.

FREE Expert Solution

Molecular orbital (MO) diagram of each molecule. 


For O2:

Step 1: The total number of valence electrons present in O2 is:

            Group             Valence Electrons

O         6A                   2 × 6 e12 e

Total:  12 valence e


Step 2: The molecular orbital diagram for O2 is:



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Problem Details

Some species consisting of just two oxygen atoms are the oxygen molecule, O 2; the peroxide ion, O22−; the superoxide ion, O 2−; and the dioxygenyl ion, O 2+. Draw an MO diagram for each, rank the species in order of increasing bond length, and find the number of unpaired electrons in each.

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Homonuclear Diatomic Molecules concept. If you need more Homonuclear Diatomic Molecules practice, you can also practice Homonuclear Diatomic Molecules practice problems.

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Based on our data, we think this problem is relevant for Professor Davidson's class at UTSA.

What textbook is this problem found in?

Our data indicates that this problem or a close variation was asked in Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition. You can also practice Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition practice problems.