🤓 Based on our data, we think this question is relevant for Professor Gonzalez's class at UM.
Step 1: Bi (EN = 2.02) is less electronegative than F (EN = 3.98) which makes it the central atom.
Step 2: The -2 charge on BiF52- indicates that the molecule has gained 2 electrons
The total valence electrons of BiF52- is:
Group Valence Electrons
Bi 5A 1 x 5 e- = 5 e-
F 7A 5 x 7 e- = 35 e-
+ 2 e-
Total: 42 valence e-
Step 3: Halogens like F, forms only 1 bond when not acting as a central atom. Bismuth is found below period 2 and can have an extended octet. Distribute the remaining electrons on the terminal atom first. Excess electrons are placed on the central atom.
Step 4: Bismuth is surrounded by 6 electron groups: 5 F atoms and 1 electron pair.
Electron Regions Hybridization Electronic Geometry Bond Angles
2 sp linear 180°
3 sp2 trigonal planar 120°
4 sp3 tetrahedral 109.5°
5 sp3d trigonal bipyramidal 90°, 120°, and 180°
6 sp3d2 octahedral 90° and 180°
Predict the shape, state the hybridization of the central atom, and give the ideal bond angle(s) and any expected deviations for BiF52−.
Frequently Asked Questions
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Our tutors have indicated that to solve this problem you will need to apply the Hybridization concept. You can view video lessons to learn Hybridization. Or if you need more Hybridization practice, you can also practice Hybridization practice problems.
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Based on our data, we think this problem is relevant for Professor Gonzalez's class at UM.
What textbook is this problem found in?
Our data indicates that this problem or a close variation was asked in Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition. You can also practice Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition practice problems.