# Problem: Predict the shape, state the hybridization of the central atom, and give the ideal bond angle(s) and any expected deviations for BiF52−.

###### FREE Expert Solution

Step 1: Bi (EN = 2.02) is less electronegative than F (EN = 3.98) which makes it the central atom.

Step 2: The -2 charge on BiF52- indicates that the molecule has gained 2 electrons

The total valence electrons of BiF52- is:

Group          Valence Electrons

Bi      5A                1 x 5 e- = 5 e-

F       7A                5 x 7 e- = 35 e-

+ 2 e-

Total: 42 valence e-

Step 3: Halogens like F, forms only 1 bond when not acting as a central atom. Bismuth is found below period 2 and can have an extended octet. Distribute the remaining electrons on the terminal atom first. Excess electrons are placed on the central atom.

Step 4: Bismuth is surrounded by 6 electron groups: 5 F atoms and 1 electron pair.

Recall:

Electron Regions   Hybridization         Electronic Geometry          Bond Angles

2                             sp                                          linear                                     180°

3                             sp2                                  trigonal planar                           120°

4                             sp3                                    tetrahedral                              109.5°

5                             sp3d                          trigonal bipyramidal           90°, 120°, and 180°

6                             sp3d2                                octahedral                         90° and 180°

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###### Problem Details

Predict the shape, state the hybridization of the central atom, and give the ideal bond angle(s) and any expected deviations for BiF52.