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Solution: Combining 0.319 mol of Fe2O3 with excess carbon produced 11.3 g of Fe.Fe2O3 + 3C → 2Fe + 3CO What is the actual yield of iron in moles? What was the theoretical yield of iron in moles? What was the percent yield? 

Problem

Combining 0.319 mol of Fe2O3 with excess carbon produced 11.3 g of Fe.

Fe2O3 + 3C → 2Fe + 3CO 

What is the actual yield of iron in moles? 

What was the theoretical yield of iron in moles? 

What was the percent yield? 

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