We are asked to determine the hybridization of each type of carbon atom.
Orbitals that can be used by the central atom:
Subshell Total # of orbitals
s _ 1 orbital
p _ _ _ 3 orbitals
d _ _ _ _ _ 5 orbitals
C→ Group 4A → 3 x 4 ve = 12 ve
H → Group 1A → 8 x 1 ve = 8 ve
Total = 20 ve
▪ 1 s orbital + 3 p orbitals = 4 orbitals (4 groups)
▪ s p p p = sp3
The hybridization of each carbon in C3H8 is sp3
C→ Group 4A → 2 x 4 ve = 8 ve
H → Group 1A → 4 x 1 ve = 4 ve
Total = 12 ve
▪ 1 s orbital + 2 p orbitals = 3 orbitals (3 groups)
▪ s p p = sp2
The hybridization of each carbon in C2H4 is sp2
Two important industrial chemicals, ethene, C2H4, and propene, C3H6, are produced by the steam (or thermal) cracking process:
2C3H8(g) ⟶ C2H4(g) + C3H6(g) + CH4(g) + H2(g)
For each of the four carbon compounds, do the following:
(c) Determine the hybridization of each type of carbon atom.
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What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Hybridization concept. You can view video lessons to learn Hybridization. Or if you need more Hybridization practice, you can also practice Hybridization practice problems.
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Our data indicates that this problem or a close variation was asked in Chemistry - OpenStax 2015th Edition. You can also practice Chemistry - OpenStax 2015th Edition practice problems.