Problem: Calculate the bond order for an ion with this configuration: (σ2s)2 (σ*2s )2 (σ2px)2 (π2py, π2pz)4 (π*2py, π*2pz)3

FREE Expert Solution

Recall that the formula for bond order is:


Bond order=12[(# of e- in bonding MO)-(# of e- in antibonding MO)]


  • e- from bonding MO = 2 + 2 + 4  = 8
  • e- from antibonding MO (*) = 2 + 3 = 5
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Problem Details

Calculate the bond order for an ion with this configuration: 

(σ2s)2 (σ*2s )2 (σ2px)(π2py, π2pz)4 (π*2py, π*2pz)3

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the MO Theory: Bond Order concept. You can view video lessons to learn MO Theory: Bond Order. Or if you need more MO Theory: Bond Order practice, you can also practice MO Theory: Bond Order practice problems.

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Based on our data, we think this problem is relevant for Professor Pavel's class at UNC.

What textbook is this problem found in?

Our data indicates that this problem or a close variation was asked in Chemistry - OpenStax 2015th Edition. You can also practice Chemistry - OpenStax 2015th Edition practice problems.