Recall that the formula for ** bond order** is:

$\overline{){\mathbf{Bond}}{\mathbf{}}{\mathbf{order}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbf{2}}\mathbf{[}\mathbf{(}\mathbf{\#}\mathbf{}\mathbf{of}\mathbf{}{\mathbf{e}}^{\mathbf{-}}\mathbf{}\mathbf{in}\mathbf{}\mathbf{bonding}\mathbf{}\mathbf{MO}\mathbf{)}\mathbf{-}\mathbf{(}\mathbf{\#}\mathbf{}\mathbf{of}\mathbf{}{\mathbf{e}}^{\mathbf{-}}\mathbf{}\mathbf{in}\mathbf{}\mathbf{antibonding}\mathbf{}\mathbf{MO}\mathbf{)}\mathbf{]}}$

- e
^{-}from bonding MO = 2 + 2 + 4 =**8** - e
^{-}from antibonding MO (*) = 2 + 3 =**5**

Calculate the bond order for an ion with this configuration:

(^{σ}2s)^{2} (^{σ*}2s )^{2} (^{σ}2px)^{2 }(^{π}2py, ^{π}2pz)^{4} (^{π*}2py, ^{π*}2pz)^{3}

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