Problem: Calculate the bond order for an ion with this configuration: (σ2s)2 (σ*2s )2 (σ2px)2 (π2py, π2pz)4 (π*2py, π*2pz)3

🤓 Based on our data, we think this question is relevant for Professor Pavel's class at UNC.

FREE Expert Solution

Recall that the formula for bond order is:


Bond order=12[(# of e- in bonding MO)-(# of e- in antibonding MO)]


  • e- from bonding MO = 2 + 2 + 4  = 8
  • e- from antibonding MO (*) = 2 + 3 = 5
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Problem Details

Calculate the bond order for an ion with this configuration: 

(σ2s)2 (σ*2s )2 (σ2px)(π2py, π2pz)4 (π*2py, π*2pz)3

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What scientific concept do you need to know in order to solve this problem?

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What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Pavel's class at UNC.

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Our data indicates that this problem or a close variation was asked in Chemistry - OpenStax 2015th Edition. You can also practice Chemistry - OpenStax 2015th Edition practice problems.