We first need to calculate the moles of HNO3 required to completely react with 0.2352 g of K2HPO4. From the balanced equation, we can see that 2 moles of HNO3 reacts with 1 mole of K2HPO4. The molar mass of K2HPO4 is 2(39.10 g/mol K) + 1.01 g/mol H + 30.97 g/mol P + 4(16.00 g/mol O) = 174.18 g/mol.
What volume of 0.08892 M HNO3 is required to react completely with 0.2352 g of potassium hydrogen phosphate?
2HNO3(aq) + K2HPO4(aq) ⟶ H2PO4(aq) + 2KNO3(aq)
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