🤓 Based on our data, we think this question is relevant for Professor Tang's class at USF.
Step 1: Calculate the amount of Br from AgBr (since all of the Br from GaBr3 is converted to AgBr):
Molar mass AgBr = mass Ag + mass Br
Molar mass AgBr = 107.87 g/mol + 79.9 g/mol = 187.77 g/mol
A sample of gallium bromide, GaBr3, weighing 0.165 g was dissolved in water and treated with silver nitrate, AgNO3, resulting in the precipitation of 0.299 g AgBr. Use these data to compute the %Ga (by mass) GaBr3.
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