For this problem, the reaction is the combustion of C3H8:
C3H8 + O2 → CO2 + H2O
This equation is not yet balanced.
Balance C: We have 3 C on the reactant side and 1 C on the product side – add a coefficient of 3 to CO2:
C3H8 + O2 → 3 CO2 + H2O
Balance H: We have 8 H on the reactant side and 2 H on the product side – add a coefficient of 4 to H2O:
C3H8 + O2 → 3 CO2 + 4 H2O
Balance O: We have 2 O on the reactant side and 3(2) + 4 = 10 O on the product side – add a coefficient of 5 to O2:
C3H8 + 5 O2 → 3 CO2 + 4 H2O
Now that we have a balanced equation, we can proceed with the problem.
Outline the steps needed to determine the limiting reactant when 30.0 g of propane, C3H8, is burned with 75.0 g of oxygen.
Determine the limiting reactant.
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Limiting Reagent concept. If you need more Limiting Reagent practice, you can also practice Limiting Reagent practice problems.
What professor is this problem relevant for?
Based on our data, we think this problem is relevant for Professor Richert's class at ASU.
What textbook is this problem found in?
Our data indicates that this problem or a close variation was asked in Chemistry - OpenStax 2015th Edition. You can also practice Chemistry - OpenStax 2015th Edition practice problems.