2 Cu(NO3)2 + 4 KI ⟶ 2 CuI + I2 + 4 KNO3
Step 1: Calculate moles of Cu(NO3)2 required to react with KI.
moles Cu(NO3)2 = 0.01686 mol
Step 2: Determine the moles of KI using mole-to-mole comparison (from the net balanced reaction).
What volume of a 0.2089 M KI solution contains enough KI to react exactly with the Cu(NO3)2 in 43.88 mL of a 0.3842 M solution of Cu(NO 3)2?
2 Cu(NO3)2 + 4 KI ⟶ 2 CuI + I 2 + 4 KNO3
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Solution Stoichiometry concept. You can view video lessons to learn Solution Stoichiometry. Or if you need more Solution Stoichiometry practice, you can also practice Solution Stoichiometry practice problems.
What professor is this problem relevant for?
Based on our data, we think this problem is relevant for Professor Giles' class at MC MARICOPA.
What textbook is this problem found in?
Our data indicates that this problem or a close variation was asked in Chemistry - OpenStax 2015th Edition. You can also practice Chemistry - OpenStax 2015th Edition practice problems.