Problem: Gallium chloride is formed by the reaction of 2.6 L of a 1.44 M solution of HCl according to the following equation: 2Ga + 6HCl ⟶ 2GaCl3 + 3H2.(a) Outline the steps necessary to determine the number of moles and mass of gallium chloride.

🤓 Based on our data, we think this question is relevant for Professor Huskey's class at RUTGERS.

Equation: 2Ga + 6HCl ⟶ 2GaCl₃ + 3H₂

$Molarity (M) = \frac{moles of solute}{Liters of solution}$

The flow of the problem is:

molarity HCl (volume HCl)⟶ mole to mole comparison ⟶ moles GaCl₃ ⟶ molar mass GaCl₃

The steps necessary to determine the number of moles and mass of gallium chloride are:

Gallium chloride is formed by the reaction of 2.6 L of a 1.44 M solution of HCl according to the following equation:

2Ga + 6HCl ⟶ 2GaCl₃ + 3H₂.

(a) Outline the steps necessary to determine the number of moles and mass of gallium chloride.

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Solution Stoichiometry concept. You can view video lessons to learn Solution Stoichiometry. Or if you need more Solution Stoichiometry practice, you can also practice Solution Stoichiometry practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Huskey's class at RUTGERS.

What textbook is this problem found in?

Our data indicates that this problem or a close variation was asked in Chemistry - OpenStax 2015th Edition. You can also practice Chemistry - OpenStax 2015th Edition practice problems.