Problem: Gallium chloride is formed by the reaction of 2.6 L of a 1.44 M solution of HCl according to the following equation: 2Ga + 6HCl ⟶  2GaCl3 + 3H2.(a) Outline the steps necessary to determine the number of moles and mass of gallium chloride.

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Equation: 2Ga + 6HCl ⟶  2GaCl3 + 3H2



Molarity (M)=moles of soluteLiters of solution


The flow of the problem is:



molarity HCl (volume HCl)⟶ mole to mole comparison ⟶  moles GaCl3 ⟶ molar mass GaCl3


The steps necessary to determine the number of moles and mass of gallium chloride are:


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Problem Details

Gallium chloride is formed by the reaction of 2.6 L of a 1.44 M solution of HCl according to the following equation: 

2Ga + 6HCl ⟶  2GaCl3 + 3H2.

(a) Outline the steps necessary to determine the number of moles and mass of gallium chloride.

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Our tutors have indicated that to solve this problem you will need to apply the Solution Stoichiometry concept. You can view video lessons to learn Solution Stoichiometry. Or if you need more Solution Stoichiometry practice, you can also practice Solution Stoichiometry practice problems.

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Based on our data, we think this problem is relevant for Professor Huskey's class at RUTGERS.

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Our data indicates that this problem or a close variation was asked in Chemistry - OpenStax 2015th Edition. You can also practice Chemistry - OpenStax 2015th Edition practice problems.