Ch.4 - Chemical Quantities & Aqueous ReactionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Balance each of the following equations according to the half-reaction method:(e) HBrO(aq) ⟶ Br−(aq) + O2(g) (in acid)

Solution: Balance each of the following equations according to the half-reaction method:(e) HBrO(aq) ⟶ Br−(aq) + O2(g) (in acid)

Problem

Balance each of the following equations according to the half-reaction method:

(e) HBrO(aq) ⟶ Br(aq) + O2(g) (in acid)

Solution

Setup the half reactions from the given reaction and balance both simultaneously

Since there's only one reactant from the initial reaction, we can use H2O as another reactant since this reaction occurs in aqueous conditions. This is necessary so we can make 2 half reactions with different reactants.

Half reactions of HBrO(aq) + H2O (l)⟶ Br(aq) + O2(g  are:

HBrO →  Br 

H2O →  O2

  • Balancing this half reactions under acidic conditions follows a particular steps:

Step 1: Balance the non H or O atoms (not necessary)

HBrO →  Br                                           H2O →  O2

Step 2: Balance O by adding H2O on the product side for the 1st eqn. 2nd equation needs 2 Os, add coefficient 2 to H2O

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