The reaction of the problem will appear as:
Mn(s) + HCl (aq) → MnClx + H2 (g)
First thing is to find the moles of Mn metal using the MW of Mn (54.94 g/mol)
A 2.747-g sample of manganese metal is reacted with excess HCl gas to produce 3.22 L H2(g) at 373 K and 0.951 atm and a manganese chloride compound (MnClx). What is the formula of the manganese chloride compound produced in the reaction?