🤓 Based on our data, we think this question is relevant for Professor Rexford's class at FSU.
Balancing this particular half reaction: Hg(l) + Br−(aq) ⟶ HgBr42−(aq), we will be applying the steps where:
Step 1: Balance the non H or O atoms (must have 4 Br on both sides)
Hg(l) + 4Br−(aq) ⟶ HgBr42−(aq)
Complete and balance each of the following half-reactions (steps 2–5 in half-reaction method):
(b) Hg(l) + Br−(aq) ⟶ HgBr42−(aq)