Problem: Given the following dataCa(s) + 2C (graphite) → CaC2 (s)                      ΔH = -62.8 kJCa(s) + 1/2 O2 (g) → CaO (s)                              ΔH = -635.5 kJCaO (s) + H2O (l) → Ca(OH)2 (aq)                     ΔH = -653.1 kJC2H2 (g) + 5/2O2 (g) → 2CO2 (g) + H2O (l)      ΔH = -1300. kJC(graphite) + O2 (g) → CO2 (g)                        ΔH = -393.5 kJCalculate ΔH for the reactionCaC2 (s) + 2H2O (l) → Ca(OH)2 (aq) + C2H2 (g)

FREE Expert Solution

To determine the ΔH for the reaction, use Hess Law. Manipulate the individual reactions such that when you add them you arrive to the required reaction.

Required reaction:  CaC2(s) + 2H2O(l)Ca(OH)2(aq) + C2H2(g)

Reaction 1: Ca(s) + 2 C (graphite) → CaC2(s) (reverse reaction)                              ΔH = -62.8 kJ (reverse sign)

(Reverse the reaction because CaC2 is on the product side in the required reaction while it is in the reactant side in Reaction 2)

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Problem Details

Given the following data

Ca(s) + 2C (graphite) → CaC(s)                      ΔH = -62.8 kJ

Ca(s) + 1/2 O2 (g) → CaO (s)                              ΔH = -635.5 kJ

CaO (s) + H2O (l) → Ca(OH)(aq)                     ΔH = -653.1 kJ

C2H2 (g) + 5/2O2 (g) → 2CO2 (g) + H2O (l)      ΔH = -1300. kJ

C(graphite) + O2 (g) → CO2 (g)                        ΔH = -393.5 kJ

Calculate ΔH for the reaction

CaC2 (s) + 2H2O (l) → Ca(OH)(aq) + C2H2 (g)

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Our data indicates that this problem or a close variation was asked in Chemistry: An Atoms First Approach - Zumdahl Atoms 1st 2nd Edition. You can also practice Chemistry: An Atoms First Approach - Zumdahl Atoms 1st 2nd Edition practice problems.