C - 12.01 (1) = 12.01
H - 1.01 (1) = 1.01
Cl - 35.45 (1) = 35.45
12.01 + 1.01 + 35.45 = 48.47 g/mol
A compound has the empirical formula CHCl. A 256-mL flask, at 373 K and 750. torr, contains 0.800 g of the gaseous
compound. Give the molecular formula.
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