We are asked to calculate the mass of urea is produced per minute by this reaction assuming 100% yield

2NH_{3}(*g*) + CO_{2}(*g*) → H_{2}NCONH_{2}(*s*) + H_{2}O(*g*)

Step 1. Calculate moles per minute of each

NH_{3}

$\overline{){\mathbf{PV}}{\mathbf{}}{\mathbf{=}}{\mathbf{}}{\mathbf{nRT}}}\phantom{\rule{0ex}{0ex}}\mathbf{n}\mathbf{}\mathbf{=}\frac{\mathbf{PV}}{\mathbf{RT}}\mathbf{}\phantom{\rule{0ex}{0ex}}\mathbf{n}\mathbf{}\mathbf{=}\frac{(90\overline{)\mathrm{atm}})(500\overline{)L})}{(0.08206{\displaystyle \frac{\overline{)L}-\overline{)\mathrm{atm}}}{\mathrm{mol}-\overline{)K}}})(223+273.15)\overline{)\mathbf{K}}}\mathbf{}$

**n = 1105.27 mol/min NH _{3}**

CO_{2}

$\overline{){\mathbf{PV}}{\mathbf{}}{\mathbf{=}}{\mathbf{}}{\mathbf{nRT}}}\phantom{\rule{0ex}{0ex}}\mathbf{n}\mathbf{}\mathbf{=}\frac{\mathbf{PV}}{\mathbf{RT}}\mathbf{}\phantom{\rule{0ex}{0ex}}\mathbf{n}\mathbf{}\mathbf{=}\frac{\mathbf{(}\mathbf{45}\mathbf{}\overline{)\mathbf{atm}}\mathbf{)}\mathbf{(}\mathbf{600}\mathbf{}\overline{)\mathbf{L}}\mathbf{)}}{\mathbf{(}\mathbf{0}\mathbf{.}\mathbf{08206}\mathbf{}{\displaystyle \frac{\overline{)L}-\overline{)\mathrm{atm}}}{\mathrm{mol}-\overline{)K}}}\mathbf{)}\mathbf{(}\mathbf{223}\mathbf{+}\mathbf{273}\mathbf{.}\mathbf{15}\mathbf{)}\overline{)\mathbf{K}}}\mathbf{}$

**n = 663.16 mol/min CO _{2}**

Step 2. Simultaneously calculate the theoretical yield and identify the limiting reactant.

Use both to calculate for H_{2}NCONH_{2}

Molar mass H_{2}NCONH_{2 }= 60.07 g/mol

Urea (H_{2}NCONH_{2}) is used extensively as a nitrogen source in fertilizers. It is produced commercially from the reaction of ammonia and carbon dioxide:

2NH_{3}(*g*) + CO_{2}(*g*) H_{2}NCONH_{2}(*s*) + H_{2}O(*g*)

Ammonia gas at 223°C and 90. atm flows into a reactor at a rate of 500. L/min. Carbon dioxide at 223°C and 45 atm flows into the reactor at a rate of 600. L/min. What mass of urea is produced per minute by this reaction assuming 100% yield?

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Our data indicates that this problem or a close variation was asked in Chemistry: An Atoms First Approach - Zumdahl Atoms 1st 2nd Edition. You can also practice Chemistry: An Atoms First Approach - Zumdahl Atoms 1st 2nd Edition practice problems.