**$\overline{)\mathbf{E}\mathbf{}\mathbf{=}\mathbf{}\mathbf{hv}}\phantom{\rule{0ex}{0ex}}\mathbf{E}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{hc}}{\mathbf{\lambda}}\phantom{\rule{0ex}{0ex}}\mathbf{E}\mathbf{}\mathbf{=}\mathbf{}\frac{(6.626\times {10}^{-34}J\xb7\overline{)s})(3.00\times {10}^{8}{\displaystyle \frac{\overline{)m}}{\overline{)s}}})}{\mathbf{671}\mathbf{}\overline{)\mathbf{nm}}\mathbf{}\mathbf{\times}{\displaystyle \frac{{\mathbf{10}}^{\mathbf{-}\mathbf{9}}\mathbf{}\overline{)\mathbf{m}}}{\mathbf{1}\mathbf{}\overline{)\mathbf{nm}}}}}$**

**E= 2.9624x10 ^{-19} J**

A lithium flame has a characteristic red color due to emission of light of wavelength 671 nm. What is the mass equivalence of 1 mol photons with this wavelength (1 J = 1 kg⋅m^{2}/s^{2})?

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