Problem: A 2.20-g sample of an unknown acid (empirical formula = C 3H4O3) is dissolved in 1.0 L of water. A titration required 25.0 mL of 0.500 M NaOH to react completely with all the acid present. Assuming the unknown acid has one acidic proton per molecule, what is the molecular formula of the unknown acid?

FREE Expert Solution

At equivalence point:

moles acid = moles base

mole acid = mole base =25 mL NaOH(10-3 L1 mL)(0.500 mol NaOH1 L NaOH)=0.0125 mol

Determine the molar mass:

MMacid=2.20 g acid0.0125 mol acid=176 g/mol

The empirical formula weight of the unknown acid is 88.062 g/mol.

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Problem Details

A 2.20-g sample of an unknown acid (empirical formula = C 3H4O3) is dissolved in 1.0 L of water. A titration required 25.0 mL of 0.500 M NaOH to react completely with all the acid present. Assuming the unknown acid has one acidic proton per molecule, what is the molecular formula of the unknown acid?

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