Problem: A 5.00-g sample of aluminum pellets (specific heat capacity = 0.89 J/°C ? g) and a 10.00-g sample of iron pellets (specific heat capacity = 0.45 J/°C ? g) are heated to 100.0°C. The mixture of hot iron and aluminum is then dropped into 97.3 g water at 22.0°C. Calculate the final temperature of the metal and water mixture, assuming no heat loss to the surroundings.

FREE Expert Solution

Step 1: Calculate the average specific heat of the metals:

Cave = CAlMass ratioAl + CFeMass ratioFeCave = (0.89Jg·°C)(5.00 g Fe15 g metal) + (0.45Jg·°C)(10.00 g Al15 g metal)

Cave = 0.60 J/g•°C


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Problem Details

A 5.00-g sample of aluminum pellets (specific heat capacity = 0.89 J/°C ? g) and a 10.00-g sample of iron pellets (specific heat capacity = 0.45 J/°C ? g) are heated to 100.0°C. The mixture of hot iron and aluminum is then dropped into 97.3 g water at 22.0°C. Calculate the final temperature of the metal and water mixture, assuming no heat loss to the surroundings.

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