Step 1: Write the total or full ionic equation.
• soluble ionic compounds separate and become ions in the chemical equation
• compounds that are aqueous can break up into ions
• insoluble compounds (solids, liquids, and gases) will not break up the solution
The given reaction is balanced:
K2C2O4(aq) + Ba(OH)2(aq) ⟶ 2 KOH(aq) + BaC2O4(s)
▪ K2C2O4(aq) → 2 K+(aq) + C2O42-(aq)
▪ Ba(OH)2(aq) → Ba2+(aq) + 2 OH-(aq)
▪ 2 KOH(aq) → 2 K+(aq) + 2 OH-(aq)
Complete Ionic Equation:
2 K+(aq) + 2 C2O42-(aq) + Ba2+(aq) + 2 OH-(aq) → 2 K+(aq) + 2 OH-(aq) + BaC2O4(s)
Step 2: Write the net ionic equation.
From the balanced molecular equations, write the complete ionic and net ionic equations for the following:
(a) K2C2O4(aq) + Ba(OH)2(aq) ⟶ 2KOH(aq) + BaC2O4(s)
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Complete Ionic Equations concept. You can view video lessons to learn Complete Ionic Equations. Or if you need more Complete Ionic Equations practice, you can also practice Complete Ionic Equations practice problems.
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Based on our data, we think this problem is relevant for Professor Gunasekera's class at UIUC.
What textbook is this problem found in?
Our data indicates that this problem or a close variation was asked in Chemistry - OpenStax 2015th Edition. You can also practice Chemistry - OpenStax 2015th Edition practice problems.