We are being asked to calculate the concentrations of the stock solution and solutions A, B, and C.
When dealing with dilution we will use the following equation:
M1 = initial concentration
V1 = initial volume
M2 = final concentration
V2 = final volume
We are going to do the following steps:
Step 1: Determine the concentration of the stock solution
Step 2: Determine the concentration of solution A
Step 3: Determine the concentration of solution B
Step 4: Determine the concentration of solution C
To calculate the concentration of the dilute solutions,
A stock solution containing Mn 2+ ions was prepared by dissolving 1.584 g pure manganese metal in nitric acid and diluting to a final volume of 1.000 L. The following solutions were then prepared by dilution:
For solution A, 50.00 mL of stock solution was diluted to 1000.0 mL.
For solution B, 10.00 mL of solution A was diluted to 250.0 mL.
For solution C, 10.00 mL of solution B was diluted to 500.0 mL.
Calculate the concentrations of the stock solution and solutions A, B, and C.
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Dilutions concept. You can view video lessons to learn Dilutions. Or if you need more Dilutions practice, you can also practice Dilutions practice problems.
What professor is this problem relevant for?
Based on our data, we think this problem is relevant for Professor Gulde's class at UB.
What textbook is this problem found in?
Our data indicates that this problem or a close variation was asked in Chemistry: An Atoms First Approach - Zumdahl Atoms 1st 2nd Edition. You can also practice Chemistry: An Atoms First Approach - Zumdahl Atoms 1st 2nd Edition practice problems.