# Problem: Describe how you would prepare 2.00 L of 0.250 M NaOH from 1.00 M NaOH stock solution.

###### FREE Expert Solution
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###### FREE Expert Solution

We are being asked to find describe how you would prepare 2.00 L of 0.250 M NaOH from 1.00 M NaOH stock solution.

When we are adding water (or solvent) to a solution to decrease its concentration, we are diluting the solution.

When dealing with dilution we will use the following equation:

$\overline{){{\mathbf{M}}}_{{\mathbf{1}}}{{\mathbf{V}}}_{{\mathbf{1}}}{\mathbf{=}}{{\mathbf{M}}}_{{\mathbf{2}}}{{\mathbf{V}}}_{{\mathbf{2}}}}$

M1 = initial concentration
V1 = initial volume
M2 = final concentration
V2 = final volume

First, we're going to calculate the initial volume of the 1.00 M NaOH stock solution to be used.

85% (491 ratings)
###### Problem Details

Describe how you would prepare 2.00 L of 0.250 M NaOH from 1.00 M NaOH stock solution.

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Dilutions concept. You can view video lessons to learn Dilutions Or if you need more Dilutions practice, you can also practice Dilutions practice problems .

How long does this problem take to solve?

Our expert Chemistry tutor, Rae-Anne took 4 minutes to solve this problem. You can follow their steps in the video explanation above.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Marin's class at UCF.

What textbook is this problem found in?

Our data indicates that this problem or a close variation was asked in . You can also practice practice problems .