Ch.3 - Chemical ReactionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Balance the following equations:(g) Al(s) + H2SO4(aq) ⟶ Al2(SO4)3(s) + H2(g)

Solution: Balance the following equations:(g) Al(s) + H2SO4(aq) ⟶ Al2(SO4)3(s) + H2(g)

Problem

Balance the following equations:

(g) Al(s) + H2SO4(aq) ⟶ Al2(SO4)3(s) + H2(g)


Solution

Unbalanced reaction:

Al(s) + H2SO4(aq) ⟶ Al2(SO4)3(s) + H2(g)

To balance, we look at each element/ion then count the number for each side. We then add a coefficient to the side with less number of that element to balance. 

Both the reactant and product side has SOor  SO42- as the polyatomic ion. We don't see any other S or O in the other compounds in the reaction aside from the ones in SO42- This means we can treat it as one particle to make our balance easy. 

View the complete written solution...