Problem: Acrylonitrile (C3H3N) is the starting material for many synthetic carpets and fabrics. It is produced by the following reaction:2 C3H6 (g) + 2 NH 3 (g) + 3 O2 (g) → 2 C3H3N (g) + 6 H2O (g)If 15.0 g C3H6, 10.0 g O 2, and 5.00 g NH 3 are reacted, what mass of acrylonitrile can be produced, assuming 100% yield?
FREE Expert Solution
- Using the balanced equation provided, we can determine the mass of C3H3N based on the limiting reactant.
The limiting reactant is the reactant that will produce the least amount of C3H3N, we can determine this by using stoichiometry and the molar masses of each reactant:
MM of C3H6
C : 12.01 x 3 = 36.03
H: 1.01 x 6 = 6.06
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MM of C3H6 : 36.03 + 6.06 = 42.09 g/mol
MM of O2: 16 x 2 = 32 g/mol
MM of NH3:
N: 14.01 x 1 = 14.01
H: 1.01 x 3 = 3.03
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MM of NH3: 14.01 + 3.03 = 17.04 g/mol
Problem Details
Acrylonitrile (C3H3N) is the starting material for many synthetic carpets and fabrics. It is produced by the following reaction:
2 C3H6 (g) + 2 NH 3 (g) + 3 O2 (g) → 2 C3H3N (g) + 6 H2O (g)
If 15.0 g C3H6, 10.0 g O 2, and 5.00 g NH 3 are reacted, what mass of acrylonitrile can be produced, assuming 100% yield?
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Limiting Reagent concept. You can view video lessons to learn Limiting Reagent. Or if you need more Limiting Reagent practice, you can also practice Limiting Reagent practice problems.
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Based on our data, we think this problem is relevant for Professor Wasalathanthri's class at UCONN.
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Our data indicates that this problem or a close variation was asked in Chemistry: An Atoms First Approach - Zumdahl Atoms 1st 2nd Edition. You can also practice Chemistry: An Atoms First Approach - Zumdahl Atoms 1st 2nd Edition practice problems.