$\overline{){\mathbf{molarity}}{\mathbf{}}{\mathbf{\left(}}{\mathbf{M}}{\mathbf{\right)}}{\mathbf{=}}\frac{\mathbf{moles}\mathbf{}\mathbf{solute}}{\mathbf{L}\mathbf{}\mathbf{solution}}}$

$\overline{){\mathbf{\%}}{\mathbf{}}{\mathbf{Mass}}{\mathbf{=}}\frac{\mathbf{mass}\mathbf{}\mathbf{of}\mathbf{}\mathbf{phenol}}{\mathbf{mass}\mathbf{}\mathbf{of}\mathbf{}\mathbf{solution}}}$

Assume **100 g of solution **→ **1.40 g phenol**

$\mathbf{1}\mathbf{.}\mathbf{40}\mathbf{\%}\mathbf{=}\frac{\mathbf{1}\mathbf{.}\mathbf{40}\mathbf{}\mathbf{g}\mathbf{}\mathbf{phenol}}{\mathbf{100}\mathbf{}\mathbf{g}\mathbf{}\mathbf{solution}}$

**Calculate moles phenol:**

**molar mass phenol = 94.11 g/mol**

$\mathbf{moles}\mathbf{}\mathbf{phenol}\mathbf{=}\mathbf{1}\mathbf{.}\mathbf{40}\mathbf{}\overline{)\mathbf{g}\mathbf{}\mathbf{phenol}}\mathbf{\times}\frac{\mathbf{1}\mathbf{}\mathbf{mol}\mathbf{}\mathbf{phenol}}{\mathbf{94}\mathbf{.}\mathbf{11}\mathbf{}\overline{)\mathbf{g}\mathbf{}\mathbf{phenol}}}$

**moles phenol**** = 0.01487 mol**

**Calculate volume solution:**

A throat spray is 1.40% by mass phenol, C_{6}H_{5}OH, in water. If the solution has a density of 0.9956 g/mL, calculate the molarity of the solution.

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