Recall that ** molarity** is the ratio of the moles of solute and the volume of solution (in liters).

$\overline{){\mathbf{Molarity}}{\mathbf{\left(}}{\mathbf{M}}{\mathbf{\right)}}{\mathbf{=}}\frac{\mathbf{moles}\mathbf{}\mathbf{of}\mathbf{}\mathbf{solute}}{\mathbf{Liters}\mathbf{}\mathbf{of}\mathbf{}\mathbf{solution}}}$

What volume of a 0.20-M K_{2}SO_{4} solution contains 57 g of K_{2}SO_{4}?

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