# Problem: Calculate ΔH°298 for the process Zn(s) + S(s) + 2O 2(g) ⟶ ZnSO4(s)from the following information:Zn(s) + S(s) ⟶ ZnS(s)                  ΔH° 298 = −206.0 kJZnS(s) + 2O2(g) ⟶ ZnSO4(s)     ΔH°298 = −776.8 kJ

###### FREE Expert Solution

Zn(s) + S(s)  ZnS(s)                  ΔH° 298 = −206.0 kJ

ZnS(s) + 2O2(g)  ZnSO4(s)       ΔH°298 = −776.8 kJ

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Zn(s) + S(s) + 2O 2(g)  ZnSO4(s)

89% (32 ratings) ###### Problem Details

Calculate ΔH°298 for the process Zn(s) + S(s) + 2O 2(g) ⟶ ZnSO4(s)

from the following information:

Zn(s) + S(s) ⟶ ZnS(s)                  ΔH° 298 = −206.0 kJ

ZnS(s) + 2O2(g) ⟶ ZnSO4(s)     ΔH°298 = −776.8 kJ

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