🤓 Based on our data, we think this question is relevant for Professor Waddell's class at UC.
Molarity is given by the formula below:
So first we have to calculate for the moles of solute. We do that by dimensional analysis using molar mass:
Determine the molarity of each of the following solutions:
(c) 20.54 g of Al(NO3)3 in 1575 mL of solution