We’re being asked to calculate the **molarity (M)** of a solution of H_{2}SO_{4}.

The molar mass of H_{2}SO_{4} is:

H_{2}SO_{4}**2** H × 1 g/mol H = 2 g/mol

**1** S × 32 g/mol S = 32 g/mol

**4** O × 16 g/mol O =__ 64 __g__/mol __

** Total: 98 g/mol**

Determine the molarity of each of the following solutions:

(b) 0.515 g of H_{2}SO_{4} in 1.00 L of solution

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