[Co(s) + 1/2O2(g) ⟶ CoO(s)]×3 ΔH°298 = −237.9kJ ×3
3 Co(s) + 3/2O2(g) ⟶
3 CoO(s) ΔH°298 = −713.7 kJ 3 CoO(s) +1/2O2(g) ⟶ Co3O4(s) ΔH°298 = −177.5kJ
Calculate ΔH°298 for the process Co3O4(s) ⟶ 3Co(s) + 2O2(g) from the following information:
Co(s) + 1/2O2(g) ⟶ CoO(s) ΔH°298 = −237.9kJ
3CoO(s) +1/2O2(g) ⟶ Co3O4(s) ΔH°298 = −177.5kJ
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