Problem: Calculate ΔH for the process Hg 2Cl2(s) ⟶ 2Hg(l) + Cl2(g) from the following information:Hg(l) + Cl2(g) ⟶ HgCl2(s) ΔH = −224 kJHg(l) + HgCl2(s) ⟶ Hg2Cl2(s) ΔH = −41.2 kJ

FREE Expert Solution

Combine the reactions and take the sum of the ΔH applying Hess' Law

Hg(l) + Cl2(g)  HgCl2(s)            ΔH = −224 kJ (reverse)

 HgCl2(s)   Hg(l) + Cl2(g)          ΔH = +224 kJ
Hg(l) + HgCl2(s)  Hg2Cl2(s)      ΔH = −41.2 kJ (reverse)

Hg2Cl2(s) ⟶  Hg(l) + HgCl2(s)     ΔH = +41.2 kJ

Combining the equations:

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Problem Details

Calculate ΔH for the process Hg 2Cl2(s) ⟶ 2Hg(l) + Cl2(g) from the following information:
Hg(l) + Cl2(g) ⟶ HgCl2(s) ΔH = −224 kJ
Hg(l) + HgCl2(s) ⟶ Hg2Cl2(s) ΔH = −41.2 kJ

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