Problem: Determine the mass of each of the following:(a) 0.0146 mol KOH

FREE Expert Solution

A mole is a quantity of a substance that contains exactly 6.022x1023 atoms or molecules.


To convert moles to grams, we will be needing the molar mass of KOH.


<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>K</mi><mo>&#xA0;</mo><mo>=</mo><mo>&#xA0;</mo><mn>1</mn><mo>&#xD7;</mo><mn>39</mn><mo>.</mo><mn>10</mn><mo>&#xA0;</mo><mfrac bevelled="true"><mi>g</mi><mrow><mi>m</mi><mi>o</mi><mi>l</mi></mrow></mfrac><mo>&#xA0;</mo><mo>=</mo><mo>&#xA0;</mo><mn>39</mn><mo>.</mo><mn>10</mn><mo>&#xA0;</mo><mfrac bevelled="true"><mi>g</mi><mrow><mi>m</mi><mi>o</mi><mi>l</mi></mrow></mfrac><mspace linebreak="newline"></mspace><mi>O</mi><mo>&#xA0;</mo><mo>=</mo><mo>&#xA0;</mo><mn>1</mn><mo>&#xD7;</mo><mn>16</mn><mo>.</mo><mn>00</mn><mo>&#xA0;</mo><mfrac bevelled="true"><mi>g</mi><mrow><mi>m</mi><mi>o</mi><mi>l</mi></mrow></mfrac><mo>&#xA0;</mo><mo>=</mo><mo>&#xA0;</mo><mn>16</mn><mo>.</mo><mn>00</mn><mo>&#xA0;</mo><mfrac bevelled="true"><mi>g</mi><mrow><mi>m</mi><mi>o</mi><mi>l</mi></mrow></mfrac><mspace linebreak="newline"></mspace><mi>H</mi><mo>&#xA0;</mo><mo>=</mo><mo>&#xA0;</mo><mn>1</mn><mo>.</mo><mn>01</mn><mo>&#xA0;</mo><mfrac bevelled="true"><mi>g</mi><mrow><mi>m</mi><mi>o</mi><mi>l</mi></mrow></mfrac><mo>&#xA0;</mo><mo>=</mo><mo>&#xA0;</mo><mn>1</mn><mo>.</mo><mn>01</mn><mo>&#xA0;</mo><mfrac bevelled="true"><mi>g</mi><mrow><mi>m</mi><mi>o</mi><mi>l</mi></mrow></mfrac><mspace linebreak="newline"></mspace><menclose mathcolor="#FF0000" notation="box"><mi>K</mi><mi>O</mi><mi>H</mi><mo>&#xA0;</mo><mo>=</mo><mo>&#xA0;</mo><mn>56</mn><mo>.</mo><mn>11</mn><mo>&#xA0;</mo><mfrac bevelled="true"><mi>g</mi><mrow><mi>m</mi><mi>o</mi><mi>l</mi></mrow></mfrac></menclose></math>


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Problem Details

Determine the mass of each of the following:

(a) 0.0146 mol KOH

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Our data indicates that this problem or a close variation was asked in Chemistry - OpenStax 2015th Edition. You can also practice Chemistry - OpenStax 2015th Edition practice problems.