# Problem: A 70.0 g piece of metal at 80.0°C is placed in 100 g of water at 22.0°C contained in a calorimeter like that shown in Figure 5.12. The metal and water come to the same temperature at 24.6°C. How much heat did the metal give up to the water? What is the specific heat of the metal?

###### FREE Expert Solution
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###### FREE Expert Solution
• Amount of heat can be calculated using the equation:

Where q is the amount of heat in J; c as specific heat in J/goC; m is mass in grams; and ΔT as change in temperature in oC

80% (394 ratings)
###### Problem Details

A 70.0 g piece of metal at 80.0°C is placed in 100 g of water at 22.0°C contained in a calorimeter like that shown in Figure 5.12. The metal and water come to the same temperature at 24.6°C. How much heat did the metal give up to the water? What is the specific heat of the metal?

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Thermal Equilibrium concept. You can view video lessons to learn Thermal Equilibrium Or if you need more Thermal Equilibrium practice, you can also practice Thermal Equilibrium practice problems .

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Based on our data, we think this problem is relevant for Professor Tsvetkov's class at FSU.

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