All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Acrylic acid (CH2=CHCOOH) is used to prepare polymers, adhesives, and paints. The first step in making acrylic acid involves the vapor-phase oxidation of propylene (CH2=CHCH3) to acrolein (CH2=CHCHO).

Solution: Acrylic acid (CH2=CHCOOH) is used to prepare polymers, adhesives, and paints. The first step in making acrylic acid involves the vapor-phase oxidation of propylene (CH2=CHCH3) to acrolein (CH2=CHCHO).

Problem

Acrylic acid (CH2=CHCOOH) is used to prepare polymers, adhesives, and paints. The first step in making acrylic acid involves the vapor-phase oxidation of propylene (CH2=CHCH3) to acrolein (CH2=CHCHO). This step is carried out at 330°C and 2.5 atm in a large bundle of tubes around which a heat-transfer agent circulates. The reactants spend an average of 1.8 s in the tubes, which have a void space of 100 ft3. How many pounds of propylene must be added per hour in a mixture whose mole fractions are 0.07 propylene, 0.35 steam, and 0.58 air?

Solution

The ideal gas law is given by:

where P = pressure in atm, V = volume in L, n = moles of gas, R = universal gas constant, and T = temperature in Kelvin.

We can use the ideal gas law to calculate the total moles of gas present. We're given:
P = 2.5 atm          T = 330˚C + 273.15 = 603.15 K          V = 100 ft3

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