# Problem: Acetylene burns in air according to the following equation:C2H2(g) + 5/2O2(g) ⟶ 2CO2(g) + H2O(g)          ΔH°rxn = −1255.8 kJGiven ΔH°f of CO2(g) = −393.5 kJ/mol and ΔH°f of H2O(g) = −241.8 kJ/mol, find ΔH°f of C2H2(g).

###### FREE Expert Solution

Recall: The enthalpy of reaction (∆H˚rxn) can be calculated from the reactants' and products' enthalpy of formation (∆H˚f) using the equation: 90% (75 ratings) ###### Problem Details

Acetylene burns in air according to the following equation:

C2H2(g) + 5/2O2(g) ⟶ 2CO2(g) + H2O(g)          ΔH°rxn = −1255.8 kJ

Given ΔH°f of CO2(g) = −393.5 kJ/mol and ΔH°f of H2O(g) = −241.8 kJ/mol, find ΔH°f of C2H2(g).

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Based on our data, we think this problem is relevant for Professor Ocando's class at QC CUNY .

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Our data indicates that this problem or a close variation was asked in Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition. You can also practice Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition practice problems.