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Solution: Calculate ΔH for2NOCl (g) ⟶ N2 (g) + O2 (g) + Cl2 (g)given the following reactions:1/2N2 (g) + 1/2O2 (g) ⟶ NO (g)         Δ H = 90.3 kJNO (g) + 1/2Cl2 (g) ⟶ NOCl (g)        Δ H = −38.6 kJ

Problem

Calculate ΔH for

2NOCl (g) ⟶ N2 (g) + O2 (g) + Cl2 (g)

given the following reactions:

1/2N2 (g) + 1/2O2 (g) ⟶ NO (g)         Δ H = 90.3 kJ

NO (g) + 1/2Cl2 (g) ⟶ NOCl (g)        Δ H = −38.6 kJ

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