Problem: A 27.7-g sample of the radiator coolant ethylene glycol releases 688 J of heat. What was the initial temperature of the sample if the final temperature is 32.5°C (c of ethylene glycol = 2.42 J/g•K)?

FREE Expert Solution

Since we are given heat, with specific heat capacity and mass, we can use the formula below to solve for the initial temperature (Ti):



Where:
Q = heat
m = mass
Cp = specific heat
Tf= Final temperature
Ti = Initial temperature

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Problem Details

A 27.7-g sample of the radiator coolant ethylene glycol releases 688 J of heat. What was the initial temperature of the sample if the final temperature is 32.5°C (c of ethylene glycol = 2.42 J/g•K)?

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Our tutors have indicated that to solve this problem you will need to apply the Calorimetry concept. You can view video lessons to learn Calorimetry. Or if you need more Calorimetry practice, you can also practice Calorimetry practice problems.

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Based on our data, we think this problem is relevant for Professor Massa's class at HUNTER.

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Our data indicates that this problem or a close variation was asked in Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition. You can also practice Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition practice problems.