Problem: Calculate q when 0.10 g of ice is cooled from 10.0°C to −75.0°C (c  ice = 2.087 J/g•K).

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Remember:              q = mcΔT

                                    m = mass (g)

                                    c = specific heat capacity → cice = 2.087 J/g•K

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Problem Details

Calculate q when 0.10 g of ice is cooled from 10.0°C to −75.0°C (c  ice = 2.087 J/g•K).

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Our tutors have indicated that to solve this problem you will need to apply the Calorimetry concept. You can view video lessons to learn Calorimetry. Or if you need more Calorimetry practice, you can also practice Calorimetry practice problems.

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Based on our data, we think this problem is relevant for Professor Larsen's class at UH.

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Our data indicates that this problem or a close variation was asked in Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition. You can also practice Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition practice problems.