# Problem: Solid iodine trichloride is prepared in two steps: first, a reaction between solid iodine and gaseous chlorine to form solid iodine monochloride; second, treatment of the solid with more chlorine gas. (c) How many grams of iodine are needed to prepare 2.45 kg of final product?

###### FREE Expert Solution

1st reaction:                         solid iodine + gaseous chlorine → solid iodine monochloride

Balanced reaction:               I2(s) + Cl2(g) → 2 ICl(s)

2nd reaction:                         treatment of the solid with more chlorine gas

Balanced reaction:               2 ICl(s) + 2 Cl2(g) → 2 ICl3(s)

1 mol of iodine produces 2 moles of ICl and 2 moles of ICl produces to moles of ICl3

molar mass ICl3 = 233.25 g/mol

molar mass I2 = 253.8 g/mol

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###### Problem Details

Solid iodine trichloride is prepared in two steps: first, a reaction between solid iodine and gaseous chlorine to form solid iodine monochloride; second, treatment of the solid with more chlorine gas.

(c) How many grams of iodine are needed to prepare 2.45 kg of final product?