Ch.3 - Chemical ReactionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Potassium nitrate decomposes on heating, producing potassium oxide and gaseous nitrogen and oxygen: 4KNO3(s) ⟶2K2O(s) + 2N2(g) + 5O2(g) To produce 56.6 kg of oxygen, how many moles of KNO3 must be hea

Solution: Potassium nitrate decomposes on heating, producing potassium oxide and gaseous nitrogen and oxygen: 4KNO3(s) ⟶2K2O(s) + 2N2(g) + 5O2(g) To produce 56.6 kg of oxygen, how many moles of KNO3 must be hea

Problem

Potassium nitrate decomposes on heating, producing potassium oxide and gaseous nitrogen and oxygen: 

4KNO3(s) ⟶2K2O(s) + 2N2(g) + 5O2(g) 

To produce 56.6 kg of oxygen, how many moles of KNO3 must be heated?

Solution

So, we have the mass of oxygen gas (product) in kg and we need to find out the number of moles of KNO3 (reactant) from it.


First, let’s have a look at the data.


https://lh5.googleusercontent.com/Kho1gH3LWo6QLswPkvTzC98ftcIm7lQD4ZvDKjEm6L7Ziq3HmHF-bQ72yjkUK-MbrNdWzqqhdotR_lHoN58jPgiJDJsS5a8tH_XwGc01LyfjQBbJ2m7syvTXbb7_qx6HRN0g0cFV


We will solve this problem through these steps:

  • Convert mass of O2 from kg to g.
  • Convert mass of O2 (in g) to mol.
  • Convert moles of O2 to moles of KNO3 using a mole ratio in the above equation.


View the complete written solution...