Problem: Bismuth oxide reacts with carbon to form bismuth metal: Bi 2O3(s) + 3C(s) ⟶2Bi(s) + 3CO(g) When 0.607 mol of Bi2O3 reacts with excess carbon, how many grams of CO form?

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We’re being asked to calculate the mass of CO form when 0.607 mol Bi2O3 reacted with excess C. Since C is in excess, we can simply ignore it in our calculations. The flow for this problem will be like this:



The flow for this problem will be like this:


Moles of Bi2O3 (mole-to-mole comparison)  Moles of CO (molar mass of O2)  Mass of CO


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Problem Details

Bismuth oxide reacts with carbon to form bismuth metal: 

Bi 2O3(s) + 3C(s) ⟶2Bi(s) + 3CO(g) 

When 0.607 mol of Bi2Oreacts with excess carbon, how many grams of CO form?

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Our data indicates that this problem or a close variation was asked in Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition. You can also practice Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition practice problems.