**Relationship between height and densities of liquids****: **

$\frac{{\mathbf{h}}_{{\mathbf{H}}_{\mathbf{2}}\mathbf{O}}}{{\mathbf{h}}_{\mathbf{Hg}}}\mathbf{=}\frac{{\mathbf{d}}_{\mathbf{Hg}}}{{\mathbf{d}}_{{\mathbf{H}}_{\mathbf{2}}\mathbf{O}}}$

$\frac{{\mathbf{h}}_{{\mathbf{H}}_{\mathbf{2}}\mathbf{O}}}{\mathbf{730}\mathbf{}\mathbf{mm}\mathbf{}}\mathbf{=}\frac{\mathbf{13}\mathbf{.}\mathbf{5}\mathbf{}\overline{)\mathbf{g}\mathbf{/}\mathbf{mL}}}{\mathbf{1}\mathbf{.}\mathbf{00}\mathbf{}\overline{)\mathbf{g}\mathbf{/}\mathbf{mL}\mathbf{}}}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}{\mathbf{h}}_{{\mathbf{H}}_{\mathbf{2}}\mathbf{O}}\mathbf{=}\mathbf{13}\mathbf{.}\mathbf{5}(730\mathrm{mm})$

**h _{H2O} = 9855 mm H_{2}O**

On a cool, rainy day, the barometric pressure is 730 mmHg. Calculate the barometric pressure in centimeters of water (cmH_{2}O) (*d* of Hg = 13.5 g/mL; *d* of H_{2}O = 1.00 g/mL).

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