# Problem: A person’s blood alcohol (C2H5OH) level can be determined by titrating a sample of blood plasma with a potassium dichromate solution. The balanced equation is16 H+  (aq) + 2 Cr2O7 2−(aq) + C2H5OH(aq) ⟶ 4 Cr3+(aq) + 2 CO2(g) + 11 H2O(l)If 35.46 mL of 0.05961 M Cr2O7 2− is required to titrate 28.00 g of plasma, what is the mass percent of alcohol in the blood?

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A person’s blood alcohol (C2H5OH) level can be determined by titrating a sample of blood plasma with a potassium dichromate solution. The balanced equation is

16 H+  (aq) + 2 Cr2O7 2−(aq) + C2H5OH(aq) ⟶ 4 Cr3+(aq) + 2 CO2(g) + 11 H2O(l)

If 35.46 mL of 0.05961 M Cr2O7 2− is required to titrate 28.00 g of plasma, what is the mass percent of alcohol in the blood?

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Our data indicates that this problem or a close variation was asked in Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition. You can also practice Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition practice problems.